ven: ((3)/(2) x+y)^4=a_(0) x^4+a_(1) x^3 y+a_(2) x^2 y^2+a_(3) x y^3+a_(4) y^4 Tinh tông: a_(0)+a_(1)+a_(2)+a_(3)+a_(4)

Ta có: <br />$(\frac {\partial }{\partial }x+y)^{4} = (\frac {\partial }{\partial }x)^{4} + 4(\frac {\partial }{\partial }x)^{3}y + 6(\frac {\partial }{\partial }x)^{2}y^{2} + 4(\frac {\partial }{\partial }x)y^{3} + y^{4}$<br /><br />Do đó:<br />$a_{0} = 1$, $a_{1} = 4$, $a_{2} = 6$, $a_{3} = 4$, $a_{4} = 1$<br /><br />Vậy đáp án đúng là: **$a_{0} = 1$, $a_{1} = 4$, $a_{2} = 6$, $a_{3} = 4$, $a_{4} = 1$** <br />