Fill <, =>. Compare: (4)/(9)-(1)/(3)... (1)/(6) Trả lời Nhập giá trị Nhập giá trị a^b (sqrt (a))/(b) (a)/(sqrt (b))

The question is asking to compare the value of $\frac {4}{9}-\frac {1}{3}$ with $\frac {1}{6}$. First, we need to calculate the value of $\frac {4}{9}-\frac {1}{3}$. To do this, we need to find a common denominator for the two fractions. The common denominator for 9 and 3 is 9. So, we rewrite $\frac {1}{3}$ as $\frac {3}{9}$. Now, we can subtract the two fractions: $\frac {4}{9}-\frac {3}{9}=\frac {1}{9}$. Now, we compare $\frac {1}{9}$ with $\frac {1}{6}$. To compare these two fractions, we can find a common denominator, which is 18. So, we rewrite $\frac {1}{9}$ as $\frac {2}{18}$ and $\frac {1}{6}$ as $\frac {3}{18}$. Now, we can compare $\frac {2}{18}$ and $\frac {3}{18}$. Since 2 is less than 3, we conclude that $\frac {2}{18}$ is less than $\frac {3}{18}$. Therefore, $\frac {1}{9}$ is less than $\frac {1}{6}$.