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Given three numbers 1984,3292,2146 The average of these numbers is __ square geqslant . leqslant pm equiv a(b)/(c) (a)/(b) sqrt ((a)/(b)) (sqrt (a))/(sqrt (b)) sqrt (n) sqrt [n](n) sqrt [n](m) a^b (sqrt (a))/(b) (a)/(sqrt (b))

Câu hỏi

Given three numbers 1984,3292,2146 The average of these numbers is __
square 
geqslant 
.
leqslant  pm  equiv  a(b)/(c) (a)/(b) sqrt ((a)/(b)) (sqrt (a))/(sqrt (b)) sqrt (n) sqrt [n](n) sqrt [n](m) a^b (sqrt (a))/(b) (a)/(sqrt (b))
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Given three numbers 1984,3292,2146 The average of these numbers is __ square geqslant . leqslant pm equiv a(b)/(c) (a)/(b) sqrt ((a)/(b)) (sqrt (a))/(sqrt (b)) sqrt (n) sqrt [n](n) sqrt [n](m) a^b (sqrt (a))/(b) (a)/(sqrt (b))

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Mạnhthầy · Hướng dẫn 5 năm

Trả lời

The average of these numbers is 2874.

Giải thích

## Step 1<br />The average of a set of numbers is calculated by adding all the numbers together and then dividing by the count of numbers. In this case, we have three numbers: 1984, 3292, and 2146.<br /><br />## Step 2<br />First, we add these three numbers together.<br />### \(1984 + 3292 + 2146 = 8622\<br />Next, we divide this sum by the count of numbers, which is 3.<br />### \(8622 \div 3 = 2874\)