to) (8)/(7)-(5)/(12)= 1(7)/(10)-(14)/(3)=

To solve these problems, we need to perform the subtraction of fractions and mixed numbers.<br /><br />1. \(\frac{8}{7} - \frac{5}{12}\)<br /><br />First, find a common denominator for the fractions. The least common multiple (LCM) of 7 and 12 is 84.<br /><br />Convert each fraction to have the common denominator of 84:<br />\[<br />\frac{8}{7} = \frac{8 \times 12}{7 \times 12} = \frac{96}{84}<br />\]<br />\[<br />\frac{5}{12} = \frac{5 \times 7}{12 \times 7} = \frac{35}{84}<br />\]<br /><br />Now subtract the fractions:<br />\[<br />\frac{96}{84} - \frac{35}{84} = \frac{96 - 35}{84} = \frac{61}{84}<br />\]<br /><br />So, \(\frac{8}{7} - \frac{5}{12} = \frac{61}{84}\).<br /><br />2. \(1\frac{7}{10} - \frac{14}{3}\)<br /><br />First, convert the mixed number to an improper fraction:<br />\[<br />1\frac{7}{10} = \frac{10}{10} + \frac{7}{10} = \frac{17}{10}<br />\]<br /><br />Next, find a common denominator for. The LCM of 10 and 3 is each fraction to have the common denominator of 30:<br />\[<br />\frac{17}{10} = \frac{17 \times 3}{10 \times 3} = \frac{51}{30}<br />\]<br />\[<br />\frac{14}{3} = \frac{14 \times 10}{3 \times 10} = \frac{140}{30}<br />\]<br /><br />Now subtract the fractions:<br />\[<br />\frac{51}{30} - \frac{140}{30} = \frac{51 - 140}{30} = \frac{-89}{30}<br />\]<br /><br />So, \(1\frac{7}{10} - \frac{14}{3} = -\frac{89}{30}\).