2) (2)/(2-b)+(2b+2)/(3b-6) 4) (5b+1)/(2b-6)+(8)/(3-b) 6 (5b-5a+24)/(3b-3a)+(8)/(a-b) 8) (bx-x+a)/(ba-a)+(1)/(1-b) (x)/(2y^2)-xy+(4y)/(x^2)-2xy (a^2+2a)/(a^3)-1-(1)/(a^2)+a+1 (ax+2x-1)/(ax-a+x-1)+(x)/(1-x) 16Y (a^2-b^2-2a+b)/(a-2+2b-ab)+(a)/(b-1) is (1)/(x-2a)+(8a^2)/(4a^2)x-x^(3)+(1)/(x+2a) 20) (x)/(a+b)+(1)/(b-a)+(ax-bx+a+b)/(a^2)-b^(2)

These are algebraic simplification problems. The main goal is to simplify each expression to its simplest form. This involves factoring, canceling out common factors, and applying the properties of fractions. <br />2) The denominators can be factored as \(2-b\) and \(3(b-2)\). The second fraction can be simplified by factoring out the common factor of 2 from the numerator.<br />4) The denominators can be factored as \(2(b-3)\) and \(3-b\). The second fraction can be simplified by factoring out the common factor of 2 from the numerator.<br />6) The denominators can be factored as \(3(b-a)\) and \(a-b\). The second fraction can be simplified by factoring out the common factor of a from the numerator.<br />8) The denominator of the first fraction can be factored as \(a(b-1)\). The second fraction can be simplified by factoring out the common factor of -1 from the denominator.<br />The fraction can be simplified by factoring the denominator as \(xy(2-y)\) and \(x^2(1-2y)\).<br />12) The denominator of the first fraction can be factored as \(a(a^2-1)\) and the second fraction's denominator can be factored as \(a^2(a+1)\).<br />I) The denominator of the first fraction can be factored as \(a(x-1)\) and the second fraction's denominator can be factored as \(1-x\).<br />The denominator of the first fraction can be factored as \(a(1-b)\) and the second fraction's denominator can be factored as \(b-1\).<br />is) The denominator of the first fraction can be factored as \(x-2a\) and the second fraction's denominator can be factored as \(4a^2(x-a)\) and \(x+2a\).<br />The denominator of the first fraction can be factored as \(a+b\) and the second fraction's denominator can be factored as \(b-a\), and the numerator can be factored as \(a(1-x)+b\).