a. Nói điện trở suất của đồng là 1,7*10^(-8)Omega*m nghĩa là gì? Tính điện trở của dây đồng dài 100m , tiết diên 0,2mm^(2) . b. Một dây dẫn bằng nhôm hình trụ, có chiều dài l=6,28m , đường kính tiết diện d=2mm , điện trờ suất p= 2,8*10^(-8)Omega . Tính điên trở của dây dẫn?

<p> <br /><br />a. The resistivity of copper refers to how substantially a copper wire of specific dimension resists the flow of electricity. The formula R = ρL/A is used to calculate resistance, where:<br /> ρ = resistivity of the material (Ω.m) (in this case it is: 1.7 × 10^-8 Ω.m),<br /> L = length of the wire (m) (specified as: 100m),<br /> A = cross-sectional area (m²) (convert 0.2 mm² into square meters: 0.2 mm² = 2 × 10^-7m²).<br />Called it a scenario.<br /><br />Using these data, the resistance: R1= ρL/A = (1.7 × 10^-8 Ω.m)(100 m) / (2 × 10^-7m²) = 8.5 Ω<br /><br />b. Similar to above, cookies and peanuts should now be considered as resistances, the resistance of an elliptic trainer of a specified quantity can be found. Extend to terminal B. Here:<br /> ρ = resistivity of the material (Ω.m) (in this case: 2.8 x 10^-8 Ω.m),<br /> L = length of the wire (m) (specified as: 6.28m),<br /> A = cross-sectional area (m²). For a cylindrical vim diameter d, A = π(d/2)² Here, the diameter would be converted to meters, numbers from different professions are matched and met collectively, meaning d is exchanged in order, reaching 2mm = 2 x 10^-3m.<br /><br />Hence, the area can be calculated: A=π((2 x 10^-3m)/2)².<br /><br />Put these values back into R1 to get the resistance value: R2= ρL/A ≊ 2.21 x 10^-3 Ω. Course it's shortcut run a shortcut up, although it lets without down collar c without D.</p>