ng không gian Oxyz , đường thẳng d : y=1+2t có một vectơ chi phương lả: d: ) x=2-t y=1+2t z=3+4t 2;1;4) B. overrightarrow (u_(3))=(2;1;3) C overrightarrow (u_(1))=(2;2;4) D overrightarrow (u_(4))=(-1;2;4)

The equation of the line is given by:<br /><br />```<br />x = 2 - t<br />y = 1 + 2t<br />z = 3 + 4t<br />```<br /><br />A direction vector of the line is given by the coefficients of the parameter 't': (-1, 2, 4).<br /><br />Therefore, the correct answer is **D. $\overrightarrow{u_{4}} = (-1; 2; 4)$**<br />