b. } 5-3 & =2018 M & =(2 x^2-2 x-31)/(}end{aligned)

Name: B. } 5-3 & =2018 M & =(2 X^2-2 X-31)/(}end{aligned)
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Question

b. } 5-3 & =2018 M & =(2 x^2-2 x-31)/(}end{aligned)

Answer 1

The equation

is incorrect as it suggests that three different numbers are equal to each other, which is not possible. Therefore, we will focus on solving the expression for

.Given:

Simplify the numerator:

So the expression becomes:

Therefore, the solution for

is:

Câu hỏi

b. } 5-3 & =2018 M & =(2 x^2-2 x-31)/(}end{aligned)

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