A TOÁN 10-Bộ CÂU HỎI ÔN TẬP THEO CẤU TRÚC 2025 Câu 1. Cho hai tập hợp A=[m+1;2m-1],B=(0;6) Có bao trị m nguyên để Asubset B KQ: square

To have A ⊂ B, we need to satisfy two conditions:1. **The infimum of A must be greater than or equal to the infimum of B:** m + 1 ≥ 0 => m ≥ -12. **The supremum of A must be less than or equal to the supremum of B:** 2m - 1 2m m < 7/2 = 3.5Combining these conditions, we have -1 ≤ m < 3.5.Since m must be an integer, the possible values for m are 0, 1, 2, and 3.Therefore, there are integer values of m that satisfy the condition A ⊂ B.