sum _(k=0)^1(2-k)= square 7 8 4 9 5 6 3

Question

sum _(k=0)^1(2-k)=
square 
7
8
4
9
5
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3

Đỗ Nam Thịnh · Accepted Answer

3 Giải thích This is a simple summation problem. The sigma notationsum, is a way of expressing a long sum in a concise way. Here, it is summing the expression (2-k) for k from 0 to 1. To solve this, we substitute the values of k into the expression and add them up: When k = 0, the expression (2-k) becomes 2 - 0 = 2. When k = 1, the expression (2-k) becomes 2 - 1 = 1. So, the sum \sum _{k=0}^{1}(2-k) is equal to 2 + 1 = 3.

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sum _(k=0)^1(2-k)= square 7 8 4 9 5 6 3

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