PTHH: Can = (1) mathrm(CuSO)_(4)+mathrm(Fe) (2) mathrm(BaCl)_(2)+mathrm(H)_(2) mathrm(SO)_(4) (3) mathrm(BaCl)_(2)+mathrm(Na)_(2) mathrm(SO)_(4) (4) mathrm(CuSO)_(4)+mathrm(NaOH)

This question involves predicting the results of several chemical reactions. <br /><br />(1) The reaction between copper sulfate (CuSO4) and iron (Fe) will result in a single displacement reaction. Iron is more reactive than copper, so it will displace copper from the copper sulfate solution, resulting in the formation of iron sulfate (FeSO4) and copper (Cu).<br /><br />(2) The reaction between barium chloride (BaCl2) and sulfuric acid (H2SO4) is a double displacement reaction. The two compounds exchange ions to form new compounds. Barium sulfate (BaSO4) and hydrochloric acid (HCl) are formed. Barium sulfateuble in water, so it will precipitate out of the solution.<br /><br />(3) The reaction between barium chloride (BaCl2) and sodium sulfate (Na2SO4) is another example of a double displacement reaction. Barium sulfate (BaSO4) and sodium chloride (NaCl) are formed. Again sulfate is insoluble in water and will precipitate out of the solution.<br /><br />(4) The reaction between copper sulfate (CuSO4) and sodium hydroxide (NaOH) is a double displacement reaction. Copper(II) hydroxide (Cu(OH)2) and sodium sulfate (Na2SO4) are formed. Copper(II) hydroxide is insoluble in water, so it will precipitate out of the solution.